Advertisements
Advertisements
प्रश्न
Factorise the following, using the identity a2 – 2ab + b2 = (a – b)2.
a2y2 – 2aby + b2
योग
Advertisements
उत्तर
We have,
a2y2 – 2aby + b2
= (ay)2 – 2 × ay × b + b2
= (ay – b)2
= (ay – b)(ay – b)
shaalaa.com
क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 7: Algebraic Expression, Identities and Factorisation - Exercise [पृष्ठ २३४]
APPEARS IN
संबंधित प्रश्न
Expand (7m − 4)2
Expand (5p – 1)2
Factorise the following using suitable identity
x2 – 8x + 16
The factors of x2 – 6x + 9 are
Using identity, find the value of (4.9)2
A square lawn has a 2 m wide path surrounding it. If the area of the path is 136 m2, find the area of lawn
1032 – 1022 = ______ × (103 – 102) = ______.
Factorise the following, using the identity a2 – 2ab + b2 = (a – b)2.
y2 – 14y + 49
Factorise the following, using the identity a2 – 2ab + b2 = (a – b)2.
p2 – 2p + 1
Factorise the following, using the identity a2 – 2ab + b2 = (a – b)2.
a2y3 – 2aby2 + b2y
