Advertisements
Advertisements
प्रश्न
Factorise the following, using the identity a2 – 2ab + b2 = (a – b)2.
p2y2 – 2py + 1
योग
Advertisements
उत्तर
We have,
p2y2 – 2py + 1
= (py)2 – 2 × py × 1 + 12
= (py – 1)2
= (py – 1)(py – 1)
shaalaa.com
क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 7: Algebraic Expression, Identities and Factorisation - Exercise [पृष्ठ २३४]
APPEARS IN
संबंधित प्रश्न
Expand the following square, using suitable identities
(b – 7)2
Evaluate the following, using suitable identity
472
a2 – b2 is equal to ______.
Square of 9x – 7xy is ______.
(a – b) ______ = a2 – 2ab + b2
(a – b)2 + ______ = a2 – b2
Factorised form of 4y2 – 12y + 9 is ______.
1032 – 1022 = ______ × (103 – 102) = ______.
Factorise the following, using the identity a2 – 2ab + b2 = (a – b)2.
x2 – 10x + 25
The curved surface area of a cylinder is 2π(y2 – 7y + 12) and its radius is (y – 3). Find the height of the cylinder (C.S.A. of cylinder = 2πrh).
