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प्रश्न
Factorise the following, using the identity a2 – 2ab + b2 = (a – b)2.
4a2 – 4ab + b2
योग
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उत्तर
We have,
4a2 – 4ab + b2
= (2a)2 – 2 × 2a × b + b2
= (2a – b)2
= (2a – b)(2a – b)
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अध्याय 7: Algebraic Expression, Identities and Factorisation - Exercise [पृष्ठ २३४]
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