Advertisements
Advertisements
प्रश्न
Factorise the following.
x2 + 4x – 77
योग
Advertisements
उत्तर
We have,
x2 + 4x – 77
= x2 + (11 – 7)x – 77
= x2 + 11x – 7x – 77
= x(x + 11) – 7(x + 11)
= (x + 11)(x – 7)
shaalaa.com
क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 7: Algebraic Expression, Identities and Factorisation - Exercise [पृष्ठ २३५]
APPEARS IN
संबंधित प्रश्न
Expand the following square, using suitable identities
(xyz – 1)2
Show that (m – n)2 + (m + n)2 = 2(m2 + n2)
Simplify: (a + b)2 – (a – b)2
Square of 3x – 4y is ______.
(a – b) ______ = a2 – 2ab + b2
Factorise the following, using the identity a2 – 2ab + b2 = (a – b)2.
x2 – 8x + 16
Factorise the following, using the identity a2 – 2ab + b2 = (a – b)2.
x2 – 10x + 25
Factorise the following, using the identity a2 – 2ab + b2 = (a – b)2.
4a2 – 4ab + b2
Verify the following:
(a – b)(a – b)(a – b) = a3 – 3a2b + 3ab2 – b3
If `x - 1/x = 7` then find the value of `x^2 + 1/x^2`.
