Advertisements
Advertisements
प्रश्न
Evaluate the following, using suitable identity
9982
योग
Advertisements
उत्तर
9982 = (1000 – 2)2
Taking a = 1000 and b = 2
(a – b)2 = a2 – 2ab + b2 becomes
= 10002 – 2(1000)(2) + 22
= 1000000 – 4000 + 4
9982 = 9,96,004
shaalaa.com
क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 3: Algebra - Exercise 3.1 [पृष्ठ ६२]
APPEARS IN
संबंधित प्रश्न
Expand: (5x - 4)2
Expand (5p – 1)2
The factors of x2 – 4x + 4 are __________
(a – 1)2 = a2 – 1
Expand the following square, using suitable identities
(b – 7)2
Expand the following square, using suitable identities
(xyz – 1)2
Square of 9x – 7xy is ______.
Factorise the following, using the identity a2 – 2ab + b2 = (a – b)2.
a2y2 – 2aby + b2
Factorise the following.
a2 – 16p – 80
If `x - 1/x = 7` then find the value of `x^2 + 1/x^2`.
