Advertisements
Advertisements
प्रश्न
(a – b)2 + ______ = a2 – b2
Advertisements
उत्तर
(a – b)2 + 2ab – 2b2 = a2 – b2
Explanation:
Let (a – b)2 + x = a2 – b2
⇒ a2 + b2 – 2ab + x = a2 – b2 ...[∵ (a – b)2 = a2 + b2 – 2ab]
⇒ x = a2 – b2 – (a2 + b2 – 2ab)
= a2 – b2 – a2 – b2 + 2ab
= 2ab – 2b2
APPEARS IN
संबंधित प्रश्न
Expand (2)2p − 3q
Expand the following square, using suitable identities
(b – 7)2
Evaluate the following, using suitable identity
472
The factors of x2 – 6x + 9 are
Factorise the following, using the identity a2 – 2ab + b2 = (a – b)2.
a2y3 – 2aby2 + b2y
Factorise the following, using the identity a2 – 2ab + b2 = (a – b)2.
`9y^2 - 4xy + (4x^2)/9`
Factorise the following.
y2 – 2y – 15
Factorise the following.
a2 – 16p – 80
If x – y = 13 and xy = 28, then find x2 + y2.
Verify the following:
(a – b)(a – b)(a – b) = a3 – 3a2b + 3ab2 – b3
