Advertisements
Advertisements
प्रश्न
(a – b)2 + ______ = a2 – b2
Advertisements
उत्तर
(a – b)2 + 2ab – 2b2 = a2 – b2
Explanation:
Let (a – b)2 + x = a2 – b2
⇒ a2 + b2 – 2ab + x = a2 – b2 ...[∵ (a – b)2 = a2 + b2 – 2ab]
⇒ x = a2 – b2 – (a2 + b2 – 2ab)
= a2 – b2 – a2 – b2 + 2ab
= 2ab – 2b2
APPEARS IN
संबंधित प्रश्न
Expand: (5x - 4)2
Expand the following square, using suitable identities
(b – 7)2
Evaluate the following, using suitable identity
9982
Factorise the following using suitable identity
x2 – 8x + 16
Simplify: (a + b)2 – (a – b)2
Factorise the following, using the identity a2 – 2ab + b2 = (a – b)2.
p2y2 – 2py + 1
Factorise the following, using the identity a2 – 2ab + b2 = (a – b)2.
`x^2/4 - 2x + 4`
Factorise the following, using the identity a2 – 2ab + b2 = (a – b)2.
`9y^2 - 4xy + (4x^2)/9`
Factorise the following.
y2 + 4y – 21
Subtract b(b2 + b – 7) + 5 from 3b2 – 8 and find the value of expression obtained for b = – 3.
