Advertisements
Advertisements
प्रश्न
Factorise the following.
y2 – 2y – 15
बेरीज
Advertisements
उत्तर
We have,
y2 – 2y – 15
= y2 + (3 – 5)y – 15
= y2 + 3y – 5y – 15
= y(y + 3) – 5(y + 3)
= (y + 3)(y – 5)
shaalaa.com
या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 7: Algebraic Expression, Identities and Factorisation - Exercise [पृष्ठ २३५]
APPEARS IN
संबंधित प्रश्न
Expand (5p – 1)2
Expand the following square, using suitable identities
(xyz – 1)2
Square of 9x – 7xy is ______.
1032 – 1022 = ______ × (103 – 102) = ______.
Factorise the following, using the identity a2 – 2ab + b2 = (a – b)2.
x2 – 10x + 25
Factorise the following, using the identity a2 – 2ab + b2 = (a – b)2.
p2 – 2p + 1
If x – y = 13 and xy = 28, then find x2 + y2.
If m – n = 16 and m2 + n2 = 400, then find mn.
Verify the following:
(a – b)(a – b)(a – b) = a3 – 3a2b + 3ab2 – b3
If `x - 1/x = 7` then find the value of `x^2 + 1/x^2`.
