Advertisements
Advertisements
प्रश्न
Factorise the following.
y2 + 4y – 21
Advertisements
उत्तर
We have,
y2 + 4y – 21
= y2 + (7 – 3)y – 21
= y2 + 7y – 3y – 21
= y(y + 7) – 3(y + 7)
= (y + 7)(y – 3)
APPEARS IN
संबंधित प्रश्न
Factorise the following using suitable identity
x2 – 8x + 16
Simplify: (a + b)2 – (a – b)2
Factorise the following, using the identity a2 – 2ab + b2 = (a – b)2.
x2 – 8x + 16
Factorise the following, using the identity a2 – 2ab + b2 = (a – b)2.
a2y2 – 2aby + b2
Factorise the following, using the identity a2 – 2ab + b2 = (a – b)2.
4y2 – 12y + 9
Factorise the following, using the identity a2 – 2ab + b2 = (a – b)2.
`9y^2 - 4xy + (4x^2)/9`
Factorise the following.
x2 – 10x + 21
Factorise the following.
x2 + 4x – 77
Verify the following:
(a – b)(a – b)(a – b) = a3 – 3a2b + 3ab2 – b3
Subtract b(b2 + b – 7) + 5 from 3b2 – 8 and find the value of expression obtained for b = – 3.
