Advertisements
Advertisements
प्रश्न
Simplify: (a + b)2 – (a – b)2
Advertisements
उत्तर
Applying the identities
(a + b)2 = a2 + 2ab + b2
(a – b)2 = a2 – 2ab + b2
(a + b)2 – (a – b)2 = a2 + 2ab + b2 – [a2 – 2ab + b2]
= a2 + 2ab + b2 – a2 + 2ab – b2
= a2(1 – 1) + ab(2 + 2) + b2(1 – 1)
= 0a2 + 4ab + 0b2 = 4ab
(a + b)2 – (a – b)2 = 4ab
APPEARS IN
संबंधित प्रश्न
Expand `("a"-1/"a")^2`
Factors of 4 – m2 are
(p – q)2 = _______________
The factors of x2 – 6x + 9 are
(a – b) ______ = a2 – 2ab + b2
Factorise the following, using the identity a2 – 2ab + b2 = (a – b)2.
x2 – 8x + 16
Factorise the following, using the identity a2 – 2ab + b2 = (a – b)2.
y2 – 14y + 49
Factorise the following, using the identity a2 – 2ab + b2 = (a – b)2.
p2y2 – 2py + 1
Factorise the following, using the identity a2 – 2ab + b2 = (a – b)2.
9x2 – 12x + 4
Verify the following:
(a – b)(a – b)(a – b) = a3 – 3a2b + 3ab2 – b3
