Advertisements
Advertisements
प्रश्न
Show that (m – n)2 + (m + n)2 = 2(m2 + n2)
Advertisements
उत्तर
Taking the L.H.S = (m – n)2 + (m + n)2
= m2 – 2mn + n2 + m2 + 2mn + n2
= m2 + n2 + m2 + n2
= 2m2 + 2n2 ...`[∵ {:(("a" + "b")^2 - 4"ab" = "a"^2 + 2"ab" + "b"^2),(("a" - "b")^2 = "a"^2 - 2"ab" + "b"^2)]`
= 2(m2 + n2)
= R.H.S
∴ (m – n)2 + (m + n)2 = 2(m2 + n2)
APPEARS IN
संबंधित प्रश्न
The factors of x2 – 4x + 4 are __________
(a – 1)2 = a2 – 1
Expand the following square, using suitable identities
(xyz – 1)2
Factorise the following using suitable identity
x2 – 8x + 16
(a – b)2 = a2 – b2
Factorise the following, using the identity a2 – 2ab + b2 = (a – b)2.
x2 – 8x + 16
Factorise the following, using the identity a2 – 2ab + b2 = (a – b)2.
p2 – 2p + 1
Factorise the following, using the identity a2 – 2ab + b2 = (a – b)2.
4a2 – 4ab + b2
Factorise the following, using the identity a2 – 2ab + b2 = (a – b)2.
a2y2 – 2aby + b2
Factorise the following, using the identity a2 – 2ab + b2 = (a – b)2.
4y2 – 12y + 9
