Advertisements
Advertisements
प्रश्न
Expand the following square, using suitable identities
(xyz – 1)2
Advertisements
उत्तर
(xyz – 1)2
Comparing (xyz – 1)2 with (a – b)2 we have a = xyz and b = 1
(a – b)2 = a2 – 2ab + b2
(xyz – 1)2 = (xyz)2 – 2(xyz)(1) + 12
(xyz – 1)2 = x2y2z2 – 2xyz + 1
APPEARS IN
संबंधित प्रश्न
The factors of x2 – 4x + 4 are __________
(a – 1)2 = a2 – 1
Expand the following square, using suitable identities
(b – 7)2
(a – b) ______ = a2 – 2ab + b2
Factorised form of 4y2 – 12y + 9 is ______.
Factorise the following, using the identity a2 – 2ab + b2 = (a – b)2.
y2 – 14y + 49
Factorise the following, using the identity a2 – 2ab + b2 = (a – b)2.
9x2 – 12x + 4
Factorise the following.
x2 – 17x + 60
The curved surface area of a cylinder is 2π(y2 – 7y + 12) and its radius is (y – 3). Find the height of the cylinder (C.S.A. of cylinder = 2πrh).
If `x - 1/x = 7` then find the value of `x^2 + 1/x^2`.
