Advertisements
Advertisements
प्रश्न
Expand the following square, using suitable identities
(xyz – 1)2
बेरीज
Advertisements
उत्तर
(xyz – 1)2
Comparing (xyz – 1)2 with (a – b)2 we have a = xyz and b = 1
(a – b)2 = a2 – 2ab + b2
(xyz – 1)2 = (xyz)2 – 2(xyz)(1) + 12
(xyz – 1)2 = x2y2z2 – 2xyz + 1
shaalaa.com
या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 3: Algebra - Exercise 3.1 [पृष्ठ ६२]
APPEARS IN
संबंधित प्रश्न
Expand `("x"-2/"x")^2`
Expand: (5x - 4)2
Factors of 4 – m2 are
Using identity, find the value of (4.9)2
(a – b) ______ = a2 – 2ab + b2
(a – b)2 = a2 – b2
Using suitable identities, evaluate the following.
(9.9)2
Factorise the following, using the identity a2 – 2ab + b2 = (a – b)2.
y2 – 14y + 49
Factorise the following.
y2 – 2y – 15
If m – n = 16 and m2 + n2 = 400, then find mn.
