Advertisements
Advertisements
Question
(a – b)2 + ______ = a2 – b2
Advertisements
Solution
(a – b)2 + 2ab – 2b2 = a2 – b2
Explanation:
Let (a – b)2 + x = a2 – b2
⇒ a2 + b2 – 2ab + x = a2 – b2 ...[∵ (a – b)2 = a2 + b2 – 2ab]
⇒ x = a2 – b2 – (a2 + b2 – 2ab)
= a2 – b2 – a2 – b2 + 2ab
= 2ab – 2b2
APPEARS IN
RELATED QUESTIONS
Expand the following square, using suitable identities
(b – 7)2
Evaluate the following, using suitable identity
9982
Show that (m – n)2 + (m + n)2 = 2(m2 + n2)
Factorise the following using suitable identity
64x2 – 112xy + 49y2
The factors of x2 – 6x + 9 are
(a – b) ______ = a2 – 2ab + b2
Using suitable identities, evaluate the following.
(9.9)2
Factorise the following, using the identity a2 – 2ab + b2 = (a – b)2.
x2 – 10x + 25
Factorise the following, using the identity a2 – 2ab + b2 = (a – b)2.
y2 – 14y + 49
Factorise the following.
x2 – 10x + 21
