Advertisements
Advertisements
प्रश्न
Factorise the following, using the identity a2 – 2ab + b2 = (a – b)2.
x2 – 10x + 25
योग
Advertisements
उत्तर
We have,
x2 – 10x + 25
= x2 – 2 × x × 5 + 52
= (x – 5)2
= (x – 5)(x – 5)
shaalaa.com
क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 7: Algebraic Expression, Identities and Factorisation - Exercise [पृष्ठ २३४]
APPEARS IN
संबंधित प्रश्न
Expand (7m − 4)2
(a – 1)2 = a2 – 1
Expand the following square, using suitable identities
(b – 7)2
Expand the following square, using suitable identities
(xyz – 1)2
Show that (m – n)2 + (m + n)2 = 2(m2 + n2)
(a – b)2 + ______ = a2 – b2
Factorise the following, using the identity a2 – 2ab + b2 = (a – b)2.
p2 – 2p + 1
Factorise the following, using the identity a2 – 2ab + b2 = (a – b)2.
a2y3 – 2aby2 + b2y
Factorise the following.
x2 – 17x + 60
Factorise the following.
x2 + 4x – 77
