Advertisements
Advertisements
प्रश्न
Factorise the following, using the identity a2 – 2ab + b2 = (a – b)2.
4y2 – 12y + 9
योग
Advertisements
उत्तर
We have,
4y2 – 12y + 9
= (2y)2 – 2 × 2y × 3 + 32
= (2y – 3)2
= (2y – 3)(2y – 3)
shaalaa.com
क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 7: Algebraic Expression, Identities and Factorisation - Exercise [पृष्ठ २३४]
APPEARS IN
संबंधित प्रश्न
Expand: (98)2
Expand the following square, using suitable identities
(b – 7)2
Expand the following square, using suitable identities
(xyz – 1)2
Evaluate the following, using suitable identity
472
The factors of x2 – 6x + 9 are
a2 – b2 is equal to ______.
Factorised form of 4y2 – 12y + 9 is ______.
Factorise the following, using the identity a2 – 2ab + b2 = (a – b)2.
9x2 – 12x + 4
Factorise the following.
y2 + 4y – 21
If `x - 1/x = 7` then find the value of `x^2 + 1/x^2`.
