Advertisements
Advertisements
प्रश्न
Factorise the following, using the identity a2 – 2ab + b2 = (a – b)2.
a2y3 – 2aby2 + b2y
योग
Advertisements
उत्तर
We have,
a2y3 – 2aby2 + b2y
= y(a2y2 – 2aby + b2)
= y[(ay)2 – 2 × ay × b + b2]
= y(ay – b)2
= y(ay – b)(ay – b)
shaalaa.com
क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 7: Algebraic Expression, Identities and Factorisation - Exercise [पृष्ठ २३५]
APPEARS IN
संबंधित प्रश्न
Expand (7m − 4)2
Expand (5p – 1)2
Expand the following square, using suitable identities
(xyz – 1)2
Evaluate the following, using suitable identity
9982
Factorised form of 4y2 – 12y + 9 is ______.
Factorise the following, using the identity a2 – 2ab + b2 = (a – b)2.
y2 – 14y + 49
Factorise the following, using the identity a2 – 2ab + b2 = (a – b)2.
p2y2 – 2py + 1
Factorise the following.
p2 – 13p – 30
If x – y = 13 and xy = 28, then find x2 + y2.
Verify the following:
(a – b)(a – b)(a – b) = a3 – 3a2b + 3ab2 – b3
