Advertisements
Advertisements
प्रश्न
Factorise the following.
x2 – 10x + 21
योग
Advertisements
उत्तर
We have,
x2 – 10x + 21
= x2 – (7 + 3)x + 21
= x2 – 7x – 3x + 21
= x(x – 7) – 3(x – 7)
= (x – 7)(x – 3)
shaalaa.com
क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 7: Algebraic Expression, Identities and Factorisation - Exercise [पृष्ठ २३५]
APPEARS IN
संबंधित प्रश्न
Expand: (5x - 4)2
Factors of 4 – m2 are
Expand the following square, using suitable identities
(b – 7)2
Expand the following square, using suitable identities
(xyz – 1)2
Evaluate the following, using suitable identity
472
(a – b) ______ = a2 – 2ab + b2
Factorise the following, using the identity a2 – 2ab + b2 = (a – b)2.
x2 – 10x + 25
Factorise the following, using the identity a2 – 2ab + b2 = (a – b)2.
p2y2 – 2py + 1
Factorise the following, using the identity a2 – 2ab + b2 = (a – b)2.
a2y2 – 2aby + b2
If m – n = 16 and m2 + n2 = 400, then find mn.
