Advertisements
Advertisements
प्रश्न
Factorise the following, using the identity a2 – 2ab + b2 = (a – b)2.
`9y^2 - 4xy + (4x^2)/9`
योग
Advertisements
उत्तर
We have,
`9y^2 - 4xy + (4x^2)/9`
= `(3y)^2 - 2 xx 3y xx (2x)/3 + ((2x)/3)^2`
= `(3y - (2x)/3)^2`
= `(3y - (2x)/3)(3y - (2x)/3)`
shaalaa.com
क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 7: Algebraic Expression, Identities and Factorisation - Exercise [पृष्ठ २३५]
APPEARS IN
संबंधित प्रश्न
Expand (2)2p − 3q
The factors of x2 – 4x + 4 are __________
The factors of x2 – 6x + 9 are
Simplify: (a + b)2 – (a – b)2
Square of 9x – 7xy is ______.
Factorise the following, using the identity a2 – 2ab + b2 = (a – b)2.
x2 – 10x + 25
Factorise the following, using the identity a2 – 2ab + b2 = (a – b)2.
y2 – 14y + 49
Factorise the following, using the identity a2 – 2ab + b2 = (a – b)2.
p2y2 – 2py + 1
Factorise the following.
x2 – 17x + 60
Factorise the following.
a2 – 16p – 80
