Advertisements
Advertisements
प्रश्न
Factorise the following expressions
y2 – 10y + 25
योग
Advertisements
उत्तर
y2 – 10y + 25 = y2 – 10y + 52
Comparing with a2 – 2ab + b2 = (a – b)2 we get a = y, b = 5
⇒ y2 – 2(y)(5) + 52 = (y – 5)2
∴ y2 – 10y + 25 = (y – 5)2
shaalaa.com
क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
APPEARS IN
संबंधित प्रश्न
Expand: (98)2
Expand the following square, using suitable identities
(b – 7)2
a2 – b2 is equal to ______.
Using suitable identities, evaluate the following.
(9.9)2
Factorise the following, using the identity a2 – 2ab + b2 = (a – b)2.
y2 – 14y + 49
Factorise the following, using the identity a2 – 2ab + b2 = (a – b)2.
p2y2 – 2py + 1
Factorise the following, using the identity a2 – 2ab + b2 = (a – b)2.
`9y^2 - 4xy + (4x^2)/9`
Factorise the following.
p2 – 13p – 30
Factorise the following.
a2 – 16p – 80
Verify the following:
(a – b)(a – b)(a – b) = a3 – 3a2b + 3ab2 – b3
