Advertisements
Advertisements
Question
Factorise the following, using the identity a2 – 2ab + b2 = (a – b)2.
p2 – 2p + 1
Sum
Advertisements
Solution
We have,
p2 – 2p + 1
= p2 – 2 × p × 1 + 12
= (p – 1)2
= (p – 1)(p – 1)
shaalaa.com
Is there an error in this question or solution?
Chapter 7: Algebraic Expression, Identities and Factorisation - Exercise [Page 234]
APPEARS IN
RELATED QUESTIONS
(p – q)2 = _______________
Expand the following square, using suitable identities
(b – 7)2
Evaluate the following, using suitable identity
9982
Factorise the following using suitable identity
x2 – 8x + 16
Simplify: (a + b)2 – (a – b)2
Factorise the following, using the identity a2 – 2ab + b2 = (a – b)2.
p2y2 – 2py + 1
Factorise the following, using the identity a2 – 2ab + b2 = (a – b)2.
`9y^2 - 4xy + (4x^2)/9`
Factorise the following.
y2 – 2y – 15
Factorise the following.
x2 – 17x + 60
If m – n = 16 and m2 + n2 = 400, then find mn.
