Advertisements
Advertisements
Question
Factorise the following, using the identity a2 – 2ab + b2 = (a – b)2.
p2 – 2p + 1
Sum
Advertisements
Solution
We have,
p2 – 2p + 1
= p2 – 2 × p × 1 + 12
= (p – 1)2
= (p – 1)(p – 1)
shaalaa.com
Is there an error in this question or solution?
Chapter 7: Algebraic Expression, Identities and Factorisation - Exercise [Page 234]
APPEARS IN
RELATED QUESTIONS
(a – 1)2 = a2 – 1
Evaluate the following, using suitable identity
472
Simplify: (a + b)2 – (a – b)2
1032 – 1022 = ______ × (103 – 102) = ______.
Factorise the following, using the identity a2 – 2ab + b2 = (a – b)2.
x2 – 10x + 25
Factorise the following, using the identity a2 – 2ab + b2 = (a – b)2.
4a2 – 4ab + b2
Factorise the following, using the identity a2 – 2ab + b2 = (a – b)2.
p2y2 – 2py + 1
Factorise the following.
y2 – 2y – 15
If m – n = 16 and m2 + n2 = 400, then find mn.
Verify the following:
(a – b)(a – b)(a – b) = a3 – 3a2b + 3ab2 – b3
