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Maharashtra State BoardSSC (English Medium) 10th Standard

Explain the concept of heteroatoms with the help of examples. - Science and Technology 1

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Question

Explain the concept of heteroatoms with the help of examples.

Answer in Brief
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Solution

  1. Many carbon compounds are formed in which atoms of elements such as oxygen, nitrogen, sulphur, halogens, etc., substitute one or more hydrogen atoms in the hydrocarbon chain.
  2. The atom of an element other than carbon and hydrogen which replaces one or more hydrogen atoms in the hydrocarbon chain is called a heteroatom.
  3. The compound acquires specific chemical properties due to these hetero atoms or the groups of atoms that contain heteroatoms, irrespective of the length and nature of the carbon chain in that compound. Therefore, these hetero atoms or the groups of atoms containing hetero atoms are called functional groups.
  4. E.g. In CH3OH, the functional group contains hetero atom ‘O’.
    In CH3CH2Cl, the functional group contains hetero atom ‘Cl’.
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Chapter 9: Carbon compounds - Solve the following Questions

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SCERT Maharashtra Science and Technology 1 [English] 10 Standard SSC
Chapter 9 Carbon compounds
Solve the following Questions | Q 5

RELATED QUESTIONS

Give names of three functional groups containing three different hetero atoms. Write name and structural formula of one example each.


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  \[\begin{array}{cc}
\ce{O}\phantom{..}\\
||\phantom{..}\\
\ce{-C-H}
\end{array}\]
  \[\begin{array}{cc}
\ce{O}\\
||\\
\ce{-C-}
\end{array}\]
  \[\begin{array}{cc}
\ce{O}\phantom{.....}\\
||\phantom{.....}\\
\ce{-C-O-H}
\end{array}\]
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  \[\begin{array}{cc}
\ce{O}\phantom{..}\\
||\phantom{..}\\
\ce{-C-O}
\end{array}\]
 

\[\begin{array}{cc}
\ce{-N-H}\\
|\phantom{..}\\
\ce{H}\phantom{..}
\end{array}\]


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(i) \[\begin{array}{cc} \ce{H}\phantom{...}\ce{H}\phantom{...}\ce{H}\\
|\phantom{....}|\phantom{....}|\\
\ce{H - C - C - C = O}\\
|\phantom{....}|\phantom{.....}\\
\ce{H}\phantom{....}\ce{H}\phantom{.....}
\end{array}\]
(ii) \[\begin{array}{cc}
\phantom{....}\ce{H}\phantom{...}\ce{H}\phantom{....}\\
\phantom{....}|\phantom{....}|\phantom{....}\\
\ce{H - C - C = O}\\|\phantom{.....}\\
\ce{H}\phantom{.....}\end{array}\]
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\[\begin{array}{cc}
\ce{CH3CH2 - C - CH3}\\\
\phantom{....}||\
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\[\ce{2C4H10 +13O2 -> 8CO2 + 10H2O}\]


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