English
Maharashtra State BoardSSC (English Medium) 10th Standard

Explain the Catenation power.

Advertisements
Advertisements

Question

Explain the Catenation power.

Explain
Advertisements

Solution

  1. Carbon has a unique ability to form strong covalent bonds with other carbon atoms; this results in the formation of big molecules. This property of carbon is called catenation power.
  2. Due to the catenation power of carbon, the compounds formed may have long straight chains of carbon, branched chains of carbon or rings of carbon.
shaalaa.com
  Is there an error in this question or solution?
Chapter 9: Carbon compounds - Solve the following Questions [Page 30]

APPEARS IN

SCERT Maharashtra Science and Technology Part 1 [English] Standard 10 Maharashtra State Board
Chapter 9 Carbon compounds
Solve the following Questions | Q 1. | Page 30

RELATED QUESTIONS

Explain the following term with an example.

Functional group


Write answer as directed.
Give any four functional groups containing oxygen as the heteroatom in it. Write name and structural formula of one example each.


Find the odd one out and give its explanation.


Write the molecular formula of the given compound.

Ethyl ethanoate


Write the molecular formula of the given compound.

Propene


Carbon compounds contain only open chains of carbon atoms.


Benzene is a cyclic unsaturated hydrocarbon.


Cyclohexane is a branched chain type of hydrocarbon.


Write scientific reason.

Ethylene is an unsaturated hydrocarbon.


Explain the concept of heteroatoms with the help of examples.


Distinguish between:

Alkane - Alkene


Write a short note.

Catenation power


Match the following.

Functional group –OH - Benzene
Heterocyclic - Potassium stearate
Unsaturated - Alcohol
Soap - Furan
Carbocyclic - Ethene

Chlorine reacts with saturated hydrocarbons at room temperature in the


Consider the following organic compounds:

(i) \[\begin{array}{cc} \ce{H}\phantom{...}\ce{H}\phantom{...}\ce{H}\\
|\phantom{....}|\phantom{....}|\\
\ce{H - C - C - C = O}\\
|\phantom{....}|\phantom{.....}\\
\ce{H}\phantom{....}\ce{H}\phantom{.....}
\end{array}\]
(ii) \[\begin{array}{cc}
\phantom{....}\ce{H}\phantom{...}\ce{H}\phantom{....}\\
\phantom{....}|\phantom{....}|\phantom{....}\\
\ce{H - C - C = O}\\|\phantom{.....}\\
\ce{H}\phantom{.....}\end{array}\]
  1. Name the functional group present in these compounds.
  2. Write the general formula for the compounds of this functional group.
  3. State the relationship between these compounds and draw the structure of any other compound having a similar functional group.

Identify heteroatom (s) in the following compound.

\[\begin{array}{cc}
\ce{CH3CH2 - C - CH3}\\\
\phantom{....}||\
\ce\\\phantom{....}{O}\end{array}\]


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×