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प्रश्न
Explain the Catenation power.
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उत्तर
- Carbon has a unique ability to form strong covalent bonds with other carbon atoms; this results in the formation of big molecules. This property of carbon is called catenation power.
- Due to the catenation power of carbon, the compounds formed may have long straight chains of carbon, branched chains of carbon or rings of carbon.
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संबंधित प्रश्न
Explain the following term with an example.
Functional group
Write answer as directed.
Give any four functional groups containing oxygen as the heteroatom in it. Write name and structural formula of one example each.
Find the odd one out and give its explanation.
Find the odd one out and give its explanation.
Write the molecular formula of the given compound.
Ethyl ethanoate
Write the molecular formula of the given compound.
Ethyl alcohol
Write the molecular formula of the given compound.
Propene
Write the molecular formula of the given compound.
Isobutane
Match the columns.
| Group A | Group B |
| 1. Straight chain hydrocarbon | a) Benzene |
| 2. Branched chain hydrocarbon | b) Propyne |
| 3. Cyclic hydrocarbon | c) Isobutylene |
Write scientific reason.
Ethylene is an unsaturated hydrocarbon.
Distinguish between:
Alkane - Alkene
Write a short note.
Catenation power
Complete the given chart with writing the correct functional group of carbon compounds.
(Ester, Aldehyde, Ketone, Carboxylic acid, Alcohol, Ether)
| -O-H | |
| \[\begin{array}{cc} \ce{O}\phantom{..}\\ ||\phantom{..}\\ \ce{-C-H} \end{array}\] |
|
| \[\begin{array}{cc} \ce{O}\\ ||\\ \ce{-C-} \end{array}\] |
|
| \[\begin{array}{cc} \ce{O}\phantom{.....}\\ ||\phantom{.....}\\ \ce{-C-O-H} \end{array}\] |
|
| -O- | |
| \[\begin{array}{cc} \ce{O}\phantom{..}\\ ||\phantom{..}\\ \ce{-C-O} \end{array}\] |
|
|
\[\begin{array}{cc} |
Which of these is true for most of the organic compounds?
Chlorine reacts with saturated hydrocarbons at room temperature in the
Identify heteroatom (s) in the following compound.
\[\ce{CH3CH2Cl}\]
One variety of household fuel is a mixture of propane (60%) and butane (40%). If 20 litres of this mixture is burnt, find the total volume of carbon dioxide added to the atmosphere. The combination reactions can be represented as:
\[\ce{C3H8 + 5O2 -> 3CO2 + 4H2O}\]
\[\ce{2C4H10 +13O2 -> 8CO2 + 10H2O}\]
