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प्रश्न
Explain the Catenation power.
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उत्तर
- Carbon has a unique ability to form strong covalent bonds with other carbon atoms; this results in the formation of big molecules. This property of carbon is called catenation power.
- Due to the catenation power of carbon, the compounds formed may have long straight chains of carbon, branched chains of carbon or rings of carbon.
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संबंधित प्रश्न
Explain the following term with an example.
Functional group
Give names of three functional groups containing three different hetero atoms. Write name and structural formula of one example each.
Define Hydrocarbons.
Find the odd one out and give its explanation.
Find the odd one out and give its explanation.
Match the columns.
| Group A | Group B |
| 1. Straight chain hydrocarbon | a) Benzene |
| 2. Branched chain hydrocarbon | b) Propyne |
| 3. Cyclic hydrocarbon | c) Isobutylene |
Carbon compounds contain only open chains of carbon atoms.
Cyclohexane is a branched chain type of hydrocarbon.
Right or wrong sentence.
LPG butane is a flammable element in.
Explain the concept of heteroatoms with the help of examples.
Distinguish between:
Saturated hydrocarbons - Unsaturated hydrocarbons
Write a short note.
Catenation power
Complete the given chart with writing the correct functional group of carbon compounds.
(Ester, Aldehyde, Ketone, Carboxylic acid, Alcohol, Ether)
| -O-H | |
| \[\begin{array}{cc} \ce{O}\phantom{..}\\ ||\phantom{..}\\ \ce{-C-H} \end{array}\] |
|
| \[\begin{array}{cc} \ce{O}\\ ||\\ \ce{-C-} \end{array}\] |
|
| \[\begin{array}{cc} \ce{O}\phantom{.....}\\ ||\phantom{.....}\\ \ce{-C-O-H} \end{array}\] |
|
| -O- | |
| \[\begin{array}{cc} \ce{O}\phantom{..}\\ ||\phantom{..}\\ \ce{-C-O} \end{array}\] |
|
|
\[\begin{array}{cc} |
An atom or a group of atoms that is responsible for the chemical characteristics of an organic compound is called ______.
Chlorine reacts with saturated hydrocarbons at room temperature in the
Which of the following is not a straight chain hydrocarbon?
Consider the following organic compounds:
| (i) \[\begin{array}{cc} \ce{H}\phantom{...}\ce{H}\phantom{...}\ce{H}\\ |\phantom{....}|\phantom{....}|\\ \ce{H - C - C - C = O}\\ |\phantom{....}|\phantom{.....}\\ \ce{H}\phantom{....}\ce{H}\phantom{.....} \end{array}\] |
(ii) \[\begin{array}{cc} \phantom{....}\ce{H}\phantom{...}\ce{H}\phantom{....}\\ \phantom{....}|\phantom{....}|\phantom{....}\\ \ce{H - C - C = O}\\|\phantom{.....}\\ \ce{H}\phantom{.....}\end{array}\] |
- Name the functional group present in these compounds.
- Write the general formula for the compounds of this functional group.
- State the relationship between these compounds and draw the structure of any other compound having a similar functional group.
Identify heteroatom (s) in the following compound.
\[\begin{array}{cc}
\ce{CH3CH2 - C - CH3}\\\
\phantom{....}||\
\ce\\\phantom{....}{O}\end{array}\]
One variety of household fuel is a mixture of propane (60%) and butane (40%). If 20 litres of this mixture is burnt, find the total volume of carbon dioxide added to the atmosphere. The combination reactions can be represented as:
\[\ce{C3H8 + 5O2 -> 3CO2 + 4H2O}\]
\[\ce{2C4H10 +13O2 -> 8CO2 + 10H2O}\]
