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प्रश्न
Explain the Catenation power.
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उत्तर
- Carbon has a unique ability to form strong covalent bonds with other carbon atoms; this results in the formation of big molecules. This property of carbon is called catenation power.
- Due to the catenation power of carbon, the compounds formed may have long straight chains of carbon, branched chains of carbon or rings of carbon.
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संबंधित प्रश्न
Define Hydrocarbons.
Find the odd one out and give its explanation.
Find the odd one out and give its explanation.
Write the molecular formula of the given compound.
Acetylene
Write the molecular formula of the given compound.
Propene
Match the columns.
| Group A | Group B |
| 1. Straight chain hydrocarbon | a) Benzene |
| 2. Branched chain hydrocarbon | b) Propyne |
| 3. Cyclic hydrocarbon | c) Isobutylene |
Benzene is a cyclic unsaturated hydrocarbon.
In LPG, butane is a flammable component.
Write scientific reason.
Ethylene is an unsaturated hydrocarbon.
Explain the concept of heteroatoms with the help of examples.
Distinguish between:
Open chain hydrocarbons - Closed chain hydrocarbons
Write a short note.
Catenation power
Write a short note.
Functional groups in carbon compounds
Match the following.
| Functional group –OH | - | Benzene |
| Heterocyclic | - | Potassium stearate |
| Unsaturated | - | Alcohol |
| Soap | - | Furan |
| Carbocyclic | - | Ethene |
Which of these is true for most of the organic compounds?
Consider the following organic compounds:
| (i) \[\begin{array}{cc} \ce{H}\phantom{...}\ce{H}\phantom{...}\ce{H}\\ |\phantom{....}|\phantom{....}|\\ \ce{H - C - C - C = O}\\ |\phantom{....}|\phantom{.....}\\ \ce{H}\phantom{....}\ce{H}\phantom{.....} \end{array}\] |
(ii) \[\begin{array}{cc} \phantom{....}\ce{H}\phantom{...}\ce{H}\phantom{....}\\ \phantom{....}|\phantom{....}|\phantom{....}\\ \ce{H - C - C = O}\\|\phantom{.....}\\ \ce{H}\phantom{.....}\end{array}\] |
- Name the functional group present in these compounds.
- Write the general formula for the compounds of this functional group.
- State the relationship between these compounds and draw the structure of any other compound having a similar functional group.
Identify heteroatom (s) in the following compound.
\[\begin{array}{cc}
\ce{CH3CH2 - C - CH3}\\\
\phantom{....}||\
\ce\\\phantom{....}{O}\end{array}\]
______ is the functional group of carboxylic acid.
One variety of household fuel is a mixture of propane (60%) and butane (40%). If 20 litres of this mixture is burnt, find the total volume of carbon dioxide added to the atmosphere. The combination reactions can be represented as:
\[\ce{C3H8 + 5O2 -> 3CO2 + 4H2O}\]
\[\ce{2C4H10 +13O2 -> 8CO2 + 10H2O}\]
