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प्रश्न
Explain the Catenation power.
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उत्तर
- Carbon has a unique ability to form strong covalent bonds with other carbon atoms; this results in the formation of big molecules. This property of carbon is called catenation power.
- Due to the catenation power of carbon, the compounds formed may have long straight chains of carbon, branched chains of carbon or rings of carbon.
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संबंधित प्रश्न
Explain the following term with an example.
Functional group
Write answer as directed.
Give any four functional groups containing oxygen as the heteroatom in it. Write name and structural formula of one example each.
Give names of three functional groups containing three different hetero atoms. Write name and structural formula of one example each.
Define Hydrocarbons.
Find the odd one out and give its explanation.
Write the molecular formula of the given compound.
Acetylene
Write the molecular formula of the given compound.
Propene
Write the molecular formula of the given compound.
Isobutane
Carbon compounds contain only open chains of carbon atoms.
Right or wrong sentence.
LPG butane is a flammable element in.
Write scientific reason.
Ethylene is an unsaturated hydrocarbon.
Write a short note.
Functional groups in carbon compounds
Complete the given chart with writing the correct functional group of carbon compounds.
(Ester, Aldehyde, Ketone, Carboxylic acid, Alcohol, Ether)
| -O-H | |
| \[\begin{array}{cc} \ce{O}\phantom{..}\\ ||\phantom{..}\\ \ce{-C-H} \end{array}\] |
|
| \[\begin{array}{cc} \ce{O}\\ ||\\ \ce{-C-} \end{array}\] |
|
| \[\begin{array}{cc} \ce{O}\phantom{.....}\\ ||\phantom{.....}\\ \ce{-C-O-H} \end{array}\] |
|
| -O- | |
| \[\begin{array}{cc} \ce{O}\phantom{..}\\ ||\phantom{..}\\ \ce{-C-O} \end{array}\] |
|
|
\[\begin{array}{cc} |
Match the following.
| Functional group –OH | - | Benzene |
| Heterocyclic | - | Potassium stearate |
| Unsaturated | - | Alcohol |
| Soap | - | Furan |
| Carbocyclic | - | Ethene |
Which of these is true for most of the organic compounds?
Chlorine reacts with saturated hydrocarbons at room temperature in the
Which of the following is not a straight chain hydrocarbon?
Identify heteroatom (s) in the following compound.
\[\begin{array}{cc}
\ce{CH3CH2 - C - CH3}\\\
\phantom{....}||\
\ce\\\phantom{....}{O}\end{array}\]
