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प्रश्न
Match the columns.
| Group A | Group B |
| 1. Straight chain hydrocarbon | a) Benzene |
| 2. Branched chain hydrocarbon | b) Propyne |
| 3. Cyclic hydrocarbon | c) Isobutylene |
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उत्तर
| Group A | Group B |
| 1. Straight chain hydrocarbon | b) Propyne |
| 2. Branched chain hydrocarbon | c) Isobutylene |
| 3. Cyclic hydrocarbon | a) Benzene |
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संबंधित प्रश्न
Find the odd one out and give its explanation.
Find the odd one out and give its explanation.
Write the molecular formula of the given compound.
Acetylene
Write the molecular formula of the given compound.
Acetone
Carbon compounds contain only open chains of carbon atoms.
Write scientific reason.
Ethylene is an unsaturated hydrocarbon.
Explain the Catenation power.
Explain the concept of heteroatoms with the help of examples.
Distinguish between:
Open chain hydrocarbons - Closed chain hydrocarbons
Distinguish between:
Alkane - Alkene
Write a short note.
Catenation power
Which of these is true for most of the organic compounds?
Chlorine reacts with saturated hydrocarbons at room temperature in the
Consider the following organic compounds:
| (i) \[\begin{array}{cc} \ce{H}\phantom{...}\ce{H}\phantom{...}\ce{H}\\ |\phantom{....}|\phantom{....}|\\ \ce{H - C - C - C = O}\\ |\phantom{....}|\phantom{.....}\\ \ce{H}\phantom{....}\ce{H}\phantom{.....} \end{array}\] |
(ii) \[\begin{array}{cc} \phantom{....}\ce{H}\phantom{...}\ce{H}\phantom{....}\\ \phantom{....}|\phantom{....}|\phantom{....}\\ \ce{H - C - C = O}\\|\phantom{.....}\\ \ce{H}\phantom{.....}\end{array}\] |
- Name the functional group present in these compounds.
- Write the general formula for the compounds of this functional group.
- State the relationship between these compounds and draw the structure of any other compound having a similar functional group.
One variety of household fuel is a mixture of propane (60%) and butane (40%). If 20 litres of this mixture is burnt, find the total volume of carbon dioxide added to the atmosphere. The combination reactions can be represented as:
\[\ce{C3H8 + 5O2 -> 3CO2 + 4H2O}\]
\[\ce{2C4H10 +13O2 -> 8CO2 + 10H2O}\]
