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प्रश्न
Find the odd one out and give its explanation.
विकल्प
CH4
C2H6
C5H12
CaCO3
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उत्तर
CaCO3
Explanation-
Calcium carbonate (CaCO3) is an inorganic compound while others are organic compounds.
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संबंधित प्रश्न
Explain the following term with an example.
Functional group
Write answer as directed.
Give any four functional groups containing oxygen as the heteroatom in it. Write name and structural formula of one example each.
Find the odd one out and give its explanation.
Write the molecular formula of the given compound.
Ethyl ethanoate
Write the molecular formula of the given compound.
Ethyl alcohol
Write the molecular formula of the given compound.
Isobutane
Match the columns.
| Group A | Group B |
| 1. Straight chain hydrocarbon | a) Benzene |
| 2. Branched chain hydrocarbon | b) Propyne |
| 3. Cyclic hydrocarbon | c) Isobutylene |
Carbon compounds contain only open chains of carbon atoms.
Benzene is a cyclic unsaturated hydrocarbon.
Explain the concept of heteroatoms with the help of examples.
Distinguish between:
Open chain hydrocarbons - Closed chain hydrocarbons
Distinguish between:
Alkane - Alkene
Which of these is true for most of the organic compounds?
Chlorine reacts with saturated hydrocarbons at room temperature in the
Consider the following organic compounds:
| (i) \[\begin{array}{cc} \ce{H}\phantom{...}\ce{H}\phantom{...}\ce{H}\\ |\phantom{....}|\phantom{....}|\\ \ce{H - C - C - C = O}\\ |\phantom{....}|\phantom{.....}\\ \ce{H}\phantom{....}\ce{H}\phantom{.....} \end{array}\] |
(ii) \[\begin{array}{cc} \phantom{....}\ce{H}\phantom{...}\ce{H}\phantom{....}\\ \phantom{....}|\phantom{....}|\phantom{....}\\ \ce{H - C - C = O}\\|\phantom{.....}\\ \ce{H}\phantom{.....}\end{array}\] |
- Name the functional group present in these compounds.
- Write the general formula for the compounds of this functional group.
- State the relationship between these compounds and draw the structure of any other compound having a similar functional group.
Identify heteroatom (s) in the following compound.
\[\ce{CH3CH2Cl}\]
One variety of household fuel is a mixture of propane (60%) and butane (40%). If 20 litres of this mixture is burnt, find the total volume of carbon dioxide added to the atmosphere. The combination reactions can be represented as:
\[\ce{C3H8 + 5O2 -> 3CO2 + 4H2O}\]
\[\ce{2C4H10 +13O2 -> 8CO2 + 10H2O}\]
