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Question
Find the odd one out and give its explanation.
Options
CH4
C2H6
C5H12
CaCO3
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Solution
CaCO3
Explanation-
Calcium carbonate (CaCO3) is an inorganic compound while others are organic compounds.
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Explain the following term with an example.
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Complete the given chart with writing the correct functional group of carbon compounds.
(Ester, Aldehyde, Ketone, Carboxylic acid, Alcohol, Ether)
| -O-H | |
| \[\begin{array}{cc} \ce{O}\phantom{..}\\ ||\phantom{..}\\ \ce{-C-H} \end{array}\] |
|
| \[\begin{array}{cc} \ce{O}\\ ||\\ \ce{-C-} \end{array}\] |
|
| \[\begin{array}{cc} \ce{O}\phantom{.....}\\ ||\phantom{.....}\\ \ce{-C-O-H} \end{array}\] |
|
| -O- | |
| \[\begin{array}{cc} \ce{O}\phantom{..}\\ ||\phantom{..}\\ \ce{-C-O} \end{array}\] |
|
|
\[\begin{array}{cc} |
Match the following.
| Functional group –OH | - | Benzene |
| Heterocyclic | - | Potassium stearate |
| Unsaturated | - | Alcohol |
| Soap | - | Furan |
| Carbocyclic | - | Ethene |
Consider the following organic compounds:
| (i) \[\begin{array}{cc} \ce{H}\phantom{...}\ce{H}\phantom{...}\ce{H}\\ |\phantom{....}|\phantom{....}|\\ \ce{H - C - C - C = O}\\ |\phantom{....}|\phantom{.....}\\ \ce{H}\phantom{....}\ce{H}\phantom{.....} \end{array}\] |
(ii) \[\begin{array}{cc} \phantom{....}\ce{H}\phantom{...}\ce{H}\phantom{....}\\ \phantom{....}|\phantom{....}|\phantom{....}\\ \ce{H - C - C = O}\\|\phantom{.....}\\ \ce{H}\phantom{.....}\end{array}\] |
- Name the functional group present in these compounds.
- Write the general formula for the compounds of this functional group.
- State the relationship between these compounds and draw the structure of any other compound having a similar functional group.
Identify heteroatom (s) in the following compound.
\[\begin{array}{cc}
\ce{CH3CH2 - C - CH3}\\\
\phantom{....}||\
\ce\\\phantom{....}{O}\end{array}\]
Identify heteroatom (s) in the following compound.
\[\ce{CH3CH2Cl}\]
Write the IUPAC name of the following:
\[\begin{array}{cc}
\ce{CH3}\phantom{...}\ce{CH3}\phantom{.......}\\
|\phantom{.......}|\phantom{.........}\\
\ce{CH2 - CH - CH2}\\
\phantom{...........}|\\
\phantom{......................}\ce{CH2}\ce{CH2}\ce{CH3}
\end{array}\]
