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प्रश्न
Write a short note.
Catenation power
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उत्तर
- The unique property of carbon atom to form covalent bonds with other carbon atoms giving rise to extremely big molecules is called catenation power.
- The covalent bond between two carbon atoms is strong and stable.
- This is the reason carbon is bestowed with catenation power.
- Due to catenation power, carbon can form a large number of compounds containing open chains or closed chains of carbon atoms.
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संबंधित प्रश्न
Explain the following term with an example.
Functional group
Define Hydrocarbons.
Write the molecular formula of the given compound.
Ethyl ethanoate
Write the molecular formula of the given compound.
Ethyl alcohol
Write the molecular formula of the given compound.
Acetone
Write the molecular formula of the given compound.
Isobutane
Carbon compounds contain only open chains of carbon atoms.
Benzene is a cyclic unsaturated hydrocarbon.
In LPG, butane is a flammable component.
Write scientific reason.
Ethylene is an unsaturated hydrocarbon.
Distinguish between:
Open chain hydrocarbons - Closed chain hydrocarbons
Write a short note.
Functional groups in carbon compounds
Complete the given chart with writing the correct functional group of carbon compounds.
(Ester, Aldehyde, Ketone, Carboxylic acid, Alcohol, Ether)
| -O-H | |
| \[\begin{array}{cc} \ce{O}\phantom{..}\\ ||\phantom{..}\\ \ce{-C-H} \end{array}\] |
|
| \[\begin{array}{cc} \ce{O}\\ ||\\ \ce{-C-} \end{array}\] |
|
| \[\begin{array}{cc} \ce{O}\phantom{.....}\\ ||\phantom{.....}\\ \ce{-C-O-H} \end{array}\] |
|
| -O- | |
| \[\begin{array}{cc} \ce{O}\phantom{..}\\ ||\phantom{..}\\ \ce{-C-O} \end{array}\] |
|
|
\[\begin{array}{cc} |
An atom or a group of atoms that is responsible for the chemical characteristics of an organic compound is called ______.
Match the following.
| Functional group –OH | - | Benzene |
| Heterocyclic | - | Potassium stearate |
| Unsaturated | - | Alcohol |
| Soap | - | Furan |
| Carbocyclic | - | Ethene |
Consider the following organic compounds:
| (i) \[\begin{array}{cc} \ce{H}\phantom{...}\ce{H}\phantom{...}\ce{H}\\ |\phantom{....}|\phantom{....}|\\ \ce{H - C - C - C = O}\\ |\phantom{....}|\phantom{.....}\\ \ce{H}\phantom{....}\ce{H}\phantom{.....} \end{array}\] |
(ii) \[\begin{array}{cc} \phantom{....}\ce{H}\phantom{...}\ce{H}\phantom{....}\\ \phantom{....}|\phantom{....}|\phantom{....}\\ \ce{H - C - C = O}\\|\phantom{.....}\\ \ce{H}\phantom{.....}\end{array}\] |
- Name the functional group present in these compounds.
- Write the general formula for the compounds of this functional group.
- State the relationship between these compounds and draw the structure of any other compound having a similar functional group.
Identify heteroatom (s) in the following compound.
\[\ce{CH3CH2Cl}\]
One variety of household fuel is a mixture of propane (60%) and butane (40%). If 20 litres of this mixture is burnt, find the total volume of carbon dioxide added to the atmosphere. The combination reactions can be represented as:
\[\ce{C3H8 + 5O2 -> 3CO2 + 4H2O}\]
\[\ce{2C4H10 +13O2 -> 8CO2 + 10H2O}\]
Write the IUPAC name of the following:
\[\begin{array}{cc}
\ce{CH3}\phantom{...}\ce{CH3}\phantom{.......}\\
|\phantom{.......}|\phantom{.........}\\
\ce{CH2 - CH - CH2}\\
\phantom{...........}|\\
\phantom{......................}\ce{CH2}\ce{CH2}\ce{CH3}
\end{array}\]
