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प्रश्न
Write a short note.
Catenation power
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उत्तर
- The unique property of carbon atom to form covalent bonds with other carbon atoms giving rise to extremely big molecules is called catenation power.
- The covalent bond between two carbon atoms is strong and stable.
- This is the reason carbon is bestowed with catenation power.
- Due to catenation power, carbon can form a large number of compounds containing open chains or closed chains of carbon atoms.
APPEARS IN
संबंधित प्रश्न
Write answer as directed.
Give any four functional groups containing oxygen as the heteroatom in it. Write name and structural formula of one example each.
Give names of three functional groups containing three different hetero atoms. Write name and structural formula of one example each.
Find the odd one out and give its explanation.
Write the molecular formula of the given compound.
Acetone
Match the columns.
| Group A | Group B |
| 1. Straight chain hydrocarbon | a) Benzene |
| 2. Branched chain hydrocarbon | b) Propyne |
| 3. Cyclic hydrocarbon | c) Isobutylene |
Carbon compounds contain only open chains of carbon atoms.
In LPG, butane is a flammable component.
Write scientific reason.
Ethylene is an unsaturated hydrocarbon.
Explain the Catenation power.
Explain the concept of heteroatoms with the help of examples.
Distinguish between:
Saturated hydrocarbons - Unsaturated hydrocarbons
Distinguish between:
Alkane - Alkene
Complete the given chart with writing the correct functional group of carbon compounds.
(Ester, Aldehyde, Ketone, Carboxylic acid, Alcohol, Ether)
| -O-H | |
| \[\begin{array}{cc} \ce{O}\phantom{..}\\ ||\phantom{..}\\ \ce{-C-H} \end{array}\] |
|
| \[\begin{array}{cc} \ce{O}\\ ||\\ \ce{-C-} \end{array}\] |
|
| \[\begin{array}{cc} \ce{O}\phantom{.....}\\ ||\phantom{.....}\\ \ce{-C-O-H} \end{array}\] |
|
| -O- | |
| \[\begin{array}{cc} \ce{O}\phantom{..}\\ ||\phantom{..}\\ \ce{-C-O} \end{array}\] |
|
|
\[\begin{array}{cc} |
Chlorine reacts with saturated hydrocarbons at room temperature in the
Consider the following organic compounds:
| (i) \[\begin{array}{cc} \ce{H}\phantom{...}\ce{H}\phantom{...}\ce{H}\\ |\phantom{....}|\phantom{....}|\\ \ce{H - C - C - C = O}\\ |\phantom{....}|\phantom{.....}\\ \ce{H}\phantom{....}\ce{H}\phantom{.....} \end{array}\] |
(ii) \[\begin{array}{cc} \phantom{....}\ce{H}\phantom{...}\ce{H}\phantom{....}\\ \phantom{....}|\phantom{....}|\phantom{....}\\ \ce{H - C - C = O}\\|\phantom{.....}\\ \ce{H}\phantom{.....}\end{array}\] |
- Name the functional group present in these compounds.
- Write the general formula for the compounds of this functional group.
- State the relationship between these compounds and draw the structure of any other compound having a similar functional group.
Identify heteroatom (s) in the following compound.
\[\begin{array}{cc}
\ce{CH3CH2 - C - CH3}\\\
\phantom{....}||\
\ce\\\phantom{....}{O}\end{array}\]
