Advertisements
Advertisements
Question
Explain how does the −OH group attached to a carbon of benzene ring activate it towards electrophilic substitution?
Advertisements
Solution 1
Phenol is considered to be a resonance hybrid of the following structures:

The +R effect of the –OH group increases the electron density on the benzene ring, which makes the attack of the electrophile easier. Hence, the presence of the –OH group activates the benzene ring towards electrophilic substitution reactions. Since the electron density at the ortho and para positions is relatively high, electrophilic substitution is mainly more at the ortho and para positions.
Solution 2
In an electrophilic substitution reaction, an electron-deficient species attacks the benzene ring, which is electron-rich. When an –OH group is attached to the benzene ring, it increases the ring's electron density, making it more reactive and a good site for electrophilic attack.
The increase in electron density can be visualised as:

Structures (I)-(V) indicate that the addition of a hydroxyl group to benzene has increased the electron density (negative charge) on the carbon atoms of the ring, particularly at C-2, C-4, and C-6. Therefore, it is said that the ring has been activated towards electrophiles, which are drawn to the increased electron density.
APPEARS IN
RELATED QUESTIONS
Give the structure of the product you would expect when the following alcohol reacts with HCl–ZnCl2.
Butan-1-ol
Account for the following:
o-nitrophenol is more steam volatile than p-nitrophenol.
Intermolecular hydrogen bonding is strongest in ______.
Phenols do not react with one of the following:
Phenol is more acidic than alcohol because ____________.
Acidity of phenol is due to ____________.
The ionization constant of phenol is higher than that of ethanol because ____________.
In the following compounds:

The order of acidity is

Strength of acidity is in order:

Which one of the following compounds has the most acid nature?
What is the correct order of reactivity of alcohols in the following reaction?
\[\ce{R-OH + HCl ->[ZnCl2] R-Cl + H2O}\]
Which is the final product ‘A’ (major) in the given reaction?

Which one of the following has the lowest pKa value?
For the pair phenol and cyclohexanol, answer the following:
Why is phenol more acidic than cyclohexanol?
Give the structure of the product you would expect when the following alcohol reacts with HCl–ZnCl2.
2-Methylbutan-2-ol
Give the structure of the product you would expect when the following alcohol reacts with HBr.
2-Methylbutan-2-ol
Compare acidity of phenol with that of ethanol.
