Advertisements
Advertisements
Question
Exercise Problem.
A racing car has a uniform acceleration of 4 ms–2. What distance it covers in 10 s after the start?
Advertisements
Solution
Given: acceleration = 4ms– 2.
time = 10s and initial velocity = 0
Formula: s = ut + 1/2 at2
Solution:
distance covered s = 0 × t + 1/2 × 4 ms– 2 × (10 s)2.
s = 1/2 × 4 ms– 2 × 100 s2
= 1/2 × 400m
= 200m
APPEARS IN
RELATED QUESTIONS
Give a scientific reason.
When an object falls freely to the ground, its acceleration is uniform.
Figure given below shows a velocity-time graph for a car starting from rest. The graph has three parts AB, BC and CD.
Which part of graph shows motion with uniform
(a) velocity (b) acceleration (c) retardation ?
A cyclist driving at 36 kmh−1 stops his motion in 2 s, by the application of brakes. Calculate
- retardation
- distance covered during the application of brakes.
The acceleration of a body is 8.5 ms-2. What does this statement mean?
Can you use the relation [B1]?
The initial velocity of a car is 10 ms-1. It moves with an acceleration of 2 ms-2. What will be its speed after 10 seconds?
The rate of change of velocity is ______.
If the velocity of a body does not change, then its acceleration is ______.
If a moving body comes to rest, then its acceleration is ______.
Acceleration is a scalar.
