Advertisements
Advertisements
प्रश्न
Exercise Problem.
A racing car has a uniform acceleration of 4 ms–2. What distance it covers in 10 s after the start?
Advertisements
उत्तर
Given: acceleration = 4ms– 2.
time = 10s and initial velocity = 0
Formula: s = ut + 1/2 at2
Solution:
distance covered s = 0 × t + 1/2 × 4 ms– 2 × (10 s)2.
s = 1/2 × 4 ms– 2 × 100 s2
= 1/2 × 400m
= 200m
APPEARS IN
संबंधित प्रश्न
Distinguish between acceleration and retardation.
Draw a graph for acceleration against time for a uniformly accelerated motion. How can it be used to find the change in speed in a certain interval of time?
A train moving with a velocity of 20 ms−1 is brought to rest by applying brakes in 5 s. Calculate the retardation.
From the diagram given below, calculate acceleration.
An aeroplane lands at 216 kmh−1 and stops after covering a runway of 2 m. Calculate the acceleration and the time, in which it comes to rest.
A car traveling at 60 km/h, stops on applying brakes in 10 seconds. What is its acceleration?
The distance covered by a body is directly proportional to the square of the time elapsed. What can you say about its acceleration?
Interpret the following graph:
Convert the following acceleration:
7200 km/h2 into m/s2
The slope of a velocity-time graph gives ______.
