Advertisements
Advertisements
प्रश्न
Exercise Problem.
A racing car has a uniform acceleration of 4 ms–2. What distance it covers in 10 s after the start?
Advertisements
उत्तर
Given: acceleration = 4ms– 2.
time = 10s and initial velocity = 0
Formula: s = ut + 1/2 at2
Solution:
distance covered s = 0 × t + 1/2 × 4 ms– 2 × (10 s)2.
s = 1/2 × 4 ms– 2 × 100 s2
= 1/2 × 400m
= 200m
APPEARS IN
संबंधित प्रश्न
What is meant by the term retardation? Name its S.I. unit.
When is the acceleration due to gravity negative?
From the velocity – time graph given below, calculate deceleration in region BC.

Define acceleration.
The speed of a car increases from 10 km/h to 64 km/h in 10 seconds. What will be its acceleration?
What happens to the stepwise increasing speed-time graph when the size of each step is made very small?
A car accelerates to a velocity of 30 m/s in 10 s and then decelerates for 20 s so that it stops. Draw a velocity-time graph to represent the motion and find:
The acceleration.
When a body starts from rest, the acceleration of the body after 2 seconds in ______ of its displacement.
The speed of a particle is constant. Will it have acceleration? Justify with an example.
When an object undergoes acceleration ______.
