Advertisements
Advertisements
प्रश्न
Exercise Problem.
A racing car has a uniform acceleration of 4 ms–2. What distance it covers in 10 s after the start?
Advertisements
उत्तर
Given: acceleration = 4ms– 2.
time = 10s and initial velocity = 0
Formula: s = ut + 1/2 at2
Solution:
distance covered s = 0 × t + 1/2 × 4 ms– 2 × (10 s)2.
s = 1/2 × 4 ms– 2 × 100 s2
= 1/2 × 400m
= 200m
APPEARS IN
संबंधित प्रश्न
If a body is moving with a constant velocity its acceleration is ______.
From the diagram given below, calculate acceleration.
Diagram is given below shows velocity – time graph of car P and Q, starting from the same place and in the same direction. Calculate the Acceleration of car P.
The acceleration of a body is 8.5 ms-2. What does this statement mean?
A car traveling at 60 km/h, stops on applying brakes in 10 seconds. What is its acceleration?
Interpret the following graph:
The slope of a velocity-time graph gives ______.
m/s2 is the unit of ______.
A car is being driven at a speed of 20ms-1 when brakes are applied to bring it to rest in 5 s. The deceleration produced in this case will be ______.
Assertion: Position-time graph of a stationary object is a straight line parallel to the time axis.
Reason: For a stationary object, the position does not change with time.
