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Karnataka Board PUCPUC Science 2nd PUC Class 12

EΘ of Cu is + 0.34V while that of Zn is – 0.76V. Explain.

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Question

EΘ of Cu is + 0.34V while that of Zn is – 0.76V. Explain.

Short/Brief Note
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Solution

High ionisation enthalpy to change \[\ce{Cu(s)}\] to \[\ce{Cu^2+}\] is not balanced by hydration enthalpy. Therefore, it exhibits a positive EΘ value. However, \[\ce{Zn}\] exhibits a lower value of ionization enthalpy because a stable 3d10 configuration is attained after losing two electrons. The hydration energy for \[\ce{Zn^2+}\] is comparable to that of \[\ce{Cu^2+}\]. Therefore, E° for Zn is negative.

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Chapter 8: The d-and f-Block Elements - Multiple Choice Questions (Type - I) [Page 111]

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NCERT Exemplar Chemistry Exemplar [English] Class 12
Chapter 8 The d-and f-Block Elements
Multiple Choice Questions (Type - I) | Q 48 | Page 111

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