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EΘ of Cu is + 0.34V while that of Zn is – 0.76V. Explain.

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प्रश्न

EΘ of Cu is + 0.34V while that of Zn is – 0.76V. Explain.

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उत्तर

High ionisation enthalpy to change \[\ce{Cu(s)}\] to \[\ce{Cu^2+}\] is not balanced by hydration enthalpy. Therefore, it exhibits a positive EΘ value. However, \[\ce{Zn}\] exhibits a lower value of ionization enthalpy because a stable 3d10 configuration is attained after losing two electrons. The hydration energy for \[\ce{Zn^2+}\] is comparable to that of \[\ce{Cu^2+}\]. Therefore, E° for Zn is negative.

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अध्याय 8: The d-and f-Block Elements - Multiple Choice Questions (Type - I) [पृष्ठ १११]

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एनसीईआरटी एक्झांप्लर Chemistry Exemplar [English] Class 12
अध्याय 8 The d-and f-Block Elements
Multiple Choice Questions (Type - I) | Q 48 | पृष्ठ १११

संबंधित प्रश्न

 
 
 

Complete the following chemical equations:

`(i) Cr_2O_7^(2-)+6Fe^(2+)+14H^+ ->`

`(ii) 2CrO_4^(2-)+2H^+ ->`

`(iii) 2MnO_4^-+5C_2O_4^(2-)+16H^+ ->`

 
 
 

Why +2 oxidation state of manganese is more stable?


In 3d series (Sc to Zn), which element has the lowest enthalpy of atomisation and why?


How would you account for the following: Transition metals form complex compounds.


Account for the following:

E° value for the Mn3+/Mn2+ couple is much more positive than that for Cr3+/Cr2+.


Why is the highest oxidation state of a metal exhibited in its oxide or fluoride only?


Which is a stronger reducing agent, Cr2+ or Fe2+ and why?


Give reasons: 

E° value for the Mn3+/Mn2+ couple is much more positive than that for Fe3+/Fe2+.


Why do transition metals exhibit higher enthalpy of atomization? 


Explain why transition metals and their compounds act as a catalyst.


Transition elements form binary compounds with halogens. Which of the following elements will form \[\ce{MF3}\] type compounds?

(i) \[\ce{Cr}\]

(ii) \[\ce{Co}\]

(iii) \[\ce{Cu}\]

(iv) \[\ce{Ni}\]


Although fluorine is more electronegative than oxygen, but the ability of oxygen to stabilise higher oxidation states exceeds that of fluorine. Why?


Match the properties given in Column I with the metals given in Column II.

  Column I (Property) Column II (Metal)
(i) Element with highest second
ionisation enthalpy
(a) \[\ce{Co}\]
(ii) Element with highest
third ionisation enthalpy
(b) \[\ce{Cr}\]
(iii) \[\ce{M}\] in \[\ce{M(CO)6}\] is (c) \[\ce{Cu}\]
(iv) Element with highest heat
of atomisation
(d) \[\ce{Zn}\]
    (e) \[\ce{Ni}\]

Answer the following question:

Which element of the first transition series has lowest enthalpy of atomisation?


On the basis of the figure given below, answer the following questions:

  1. Why Manganese has lower melting point than Chromium?
  2. Why do transition metals of 3d series have lower melting points as compared to 4d series?
  3. In the third transition series, identify and name the metal with the highest melting point.

Which one of the following characters tie of the transition metal is associated with higher catalytic activity?


Consider the following standard electrode potential values:

\[\ce{Fe^{3+}_{ (aq)} + e^- -> Fe^{2+}_{ (aq)}}\], E0 = +0.77 V

\[\ce{MnO^{-4}_{ (aq)} + 8H^+ + 5e^- -> Mn^{2+}_{ (aq)} + 4H2O_{(l)}}\], E0 = +1.51 V

What is the cell potential for the redox reaction?


Account for the following:

Zirconium (Zr) and Hafnium (Hf) are difficult to separate.


A coordination compound has the formula \[\ce{CoCl3.4NH3}\]. It precipitates silver ions as AgCl and its molar conductance corresponds to a total of two ions.

Based on this information, answer the following question:

  1. Deduce the structural formula of the complex compound.
  2. Write the IUPAC name of the complex compound.
  3. Draw the geometrical isomers of the complex compound.

The E° value for the Mn2+/Mn2+ couple is more positive than that of Cr3+/Cr2+ or Fe3+/Fe2+ due to the change of:


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