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प्रश्न
How would you account for the following?
Transition metals exhibit variable oxidation states.
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उत्तर
(i) The variable oxidation states of transition elements are due to the participation of ns and (n−1)d-electrons in bonding. Lower oxidation state is exhibited when ns-electrons take part in bonding. Higher oxidation states are exhibited when (n − 1) d-electrons take part in bonding.
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संबंधित प्रश्न
The `E_((M^(2+)//M))^Θ` value for copper is positive (+0.34 V). What is possibly the reason for this? (Hint: consider its high ΔaHΘ and low ΔhydHΘ)
Explain briefly how +2 state becomes more and more stable in the first half of the first row transition elements with increasing atomic number?
What are alloys?
Explain why Zn2+ salts are white whereas Cu2+ salts are coloured.
Which of the following statements is not correct?
Although fluorine is more electronegative than oxygen, but the ability of oxygen to stabilise higher oxidation states exceeds that of fluorine. Why?
Give reasons for the following statement:
Zn, Cd, and Hg are soft metals.
Why Zn, Cd and Hg are not called transition metals?
Assertion (A): Transition metals show their highest oxidation state with oxygen.
Reason (R): The ability of oxygen to form multiple bonds to metals.
Account for the following:
Copper has an exceptionally positive `"E"_("M"^(2+)//"M")^0` value.
