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Question
Diagram shows a velocity – time graph for a car starting from rest. The graph has three sections AB, BC and CD.
Compare the distance travelled in section BC with the distance travelled in section AB.
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Solution
`"Distance travelled in part BC"/"Distance travelled in part AB"=("v"_0xx"t")/(1/2xx"t"xx"v"_0)=2/1=2:1`
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