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Question
Determine where `bb(bara)` and `bb(barb)` are orthogonal, parallel or neither.
`bara = -3/5hati + 1/2hatj + 1/3hatk , barb = 5hati + 4hatj + 3hatk`
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Solution
`bara . barb = (-3/5hati + 1/2hatj + 1/3hatk).(5hati + 4hatj + 3hatk)`
= `(-3/5)(5) + (1/2)(4) + (1/3)(3)`
= −3 + 2 + 1
= 0
Since, `bara, barb` are non-zero vectors and `bara.barb` = 0.
`bara` is orthogonal to `barb`.
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