Question

Determine where `bb(bara)` and `bb(barb)` are orthogonal, parallel or neither.

`bara = -3/5hati + 1/2hatj + 1/3hatk ,  barb = 5hati + 4hatj + 3hatk`

Answer 1

`bara . barb = (-3/5hati + 1/2hatj + 1/3hatk).(5hati + 4hatj + 3hatk)`

= `(-3/5)(5) + (1/2)(4) + (1/3)(3)`

= −3 + 2 + 1

= 0

Since, `bara, barb` are non-zero vectors and `bara.barb` = 0.

`bara` is orthogonal to `barb`.