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Determine the order and degree of the following differential equation: dydxdydx(d2ydx2)2+cos(dydx)=0

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Question

Determine the order and degree of the following differential equation:

`(("d"^2"y")/"dx"^2)^2 + cos ("dy"/"dx") = 0`

Sum
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Solution

The given D.E. is

`(("d"^2"y")/"dx"^2)^2 + cos ("dy"/"dx") = 0`

This D.E. has highest order derivative `("d"^2"y")/"dx"^2`.

∴ order = 2

Since, this D.E. cannot be expressed as a polynomial in differential coefficients, the degree is not defined.

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Chapter 6: Differential Equations - Exercise 6.1 [Page 193]

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