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Question
The order and degree of the differential equation `[1 + ((dy)/(dx))^3]^(2/3) = 8((d^3y)/(dx^3))` are respectively ______.
Options
3, 1
1, 3
3, 3
1, 1
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Solution
The order and degree of the differential equation `[1 + ((dy)/(dx))^3]^(2/3) = 8((d^3y)/(dx^3))` are respectively 3, 3.
Explanation:
Given: `[1 + ((dy)/(dx))^3]^(2/3) = 8((d^3y)/(dx^3))`
Taking cube on both sides
`[1 + ((dy)/(dx))^3]^2 = 8((d^3y)/(dx^3))^3`
∴ Order = 3
Degree = 3.
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