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The degree of the differential equation [1+(dydx)2]3=(d2ydx2)2 is ______. - Mathematics

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Question

The degree of the differential equation `[1 + (dy/dx)^2]^3 = ((d^2y)/(dx^2))^2` is ______.

Options

  • 4

  • `3/2`

  • 2

  • Not defined

MCQ
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Solution

The degree of the differential equation `[1 + (dy/dx)^2]^3 = ((d^2y)/(dx^2))^2` is 2.

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2023-2024 (March) Board Sample Paper

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