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Question
Find the order and degree of the following differential equation:
`[ (d^3y)/dx^3 + x]^(3/2) = (d^2y)/dx^2`
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Solution
`[ d^3y/dx^3 + x]^(3/2) = (d^2y)/dx^2`
Squaring on both sides, we get
`[(d^3y)/dx^3 + x]^3 = ((d^2y)/dx^2)^2`
By definition of order and degree,
Order : 3 ; Degree : 3
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