Find the order and degree of the following differential equation: [d3ydx3+x]32=d2ydx2

प्रश्न

Find the order and degree of the following differential equation:

`[ (d^3y)/dx^3 + x]^(3/2) = (d^2y)/dx^2`

बेरीज

उत्तर

`[ d^3y/dx^3 + x]^(3/2) = (d^2y)/dx^2`

Squaring on both sides, we get

`[(d^3y)/dx^3 + x]^3 = ((d^2y)/dx^2)^2`

By definition of order and degree,

Order : 3 ; Degree : 3

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Order and Degree of a Differential Equation

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Q 4.01 Q 3.6 Q 4.01

पाठ 8: Differential Equation and Applications - Miscellaneous Exercise 8 [पृष्ठ १७२]

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बालभारती Mathematics and Statistics 1 (Commerce) [English] Standard 12 Maharashtra State Board

पाठ 8 Differential Equation and Applications
Miscellaneous Exercise 8 | Q 4.01 | पृष्ठ १७२

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