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Determine the order and degree of the following differential equation: dydxdydx(d2ydx2)2+cos(dydx)=0 - Mathematics and Statistics

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प्रश्न

Determine the order and degree of the following differential equation:

`(("d"^2"y")/"dx"^2)^2 + cos ("dy"/"dx") = 0`

बेरीज
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उत्तर

The given D.E. is

`(("d"^2"y")/"dx"^2)^2 + cos ("dy"/"dx") = 0`

This D.E. has highest order derivative `("d"^2"y")/"dx"^2`.

∴ order = 2

Since, this D.E. cannot be expressed as a polynomial in differential coefficients, the degree is not defined.

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पाठ 6: Differential Equations - Exercise 6.1 [पृष्ठ १९३]

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बालभारती Mathematics and Statistics 2 (Arts and Science) [English] Standard 12 Maharashtra State Board
पाठ 6 Differential Equations
Exercise 6.1 | Q 7 | पृष्ठ १९३

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