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प्रश्न
Determine the order and degree of the following differential equation:
`(("d"^2"y")/"dx"^2)^2 + cos ("dy"/"dx") = 0`
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उत्तर
The given D.E. is
`(("d"^2"y")/"dx"^2)^2 + cos ("dy"/"dx") = 0`
This D.E. has highest order derivative `("d"^2"y")/"dx"^2`.
∴ order = 2
Since, this D.E. cannot be expressed as a polynomial in differential coefficients, the degree is not defined.
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