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महाराष्ट्र राज्य शिक्षण मंडळएचएससी विज्ञान (सामान्य) इयत्ता १२ वी

Determine the order and degree of the following differential equation: [1+(dydx)2]32=8d2ydx2

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प्रश्न

Determine the order and degree of the following differential equation:

`[1 + (dy/dx)^2]^(3/2) = 8(d^2y)/dx^2`

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उत्तर

The given D.E. is `[1 + (dy/dx)^2]^(3/2) = 8(d^2y)/dx^2`

On squaring both sides, we get

`[1 + (dy/dx)^2]^3 = 8^2.((d^2y)/dx^2)^2`

This D.E. has highest order derivative `(d^2y)/dx^2` with power 2.

∴ The given D.E. has order 2 and degree 2.

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पाठ 6: Differential Equations - Exercise 6.1 [पृष्ठ १९३]

व्हिडिओ ट्यूटोरियलVIEW ALL [3]

संबंधित प्रश्‍न

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