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महाराष्ट्र राज्य शिक्षण मंडळएचएससी विज्ञान (सामान्य) इयत्ता १२ वी

Determine the order and degree of the following differential equation: (y''')2 + 3y'' + 3xy' + 5y = 0

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प्रश्न

Determine the order and degree of the following differential equation:

(y''')2 + 3y'' + 3xy' + 5y = 0

बेरीज
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उत्तर

The given D.E. is (y''')2 + 3y'' + 3xy' + 5y = 0

This can be written as:

`((d^3y)/dx^3)^2 + 3(d^2y)/dx^2 + 3x(dy/dx) + 5y` = 0

This D.E. has highest order derivative `(d^3y)/dx^3` with power 2.

∴ The given D.E. has order 3 and degree 2.

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पाठ 6: Differential Equations - Exercise 6.1 [पृष्ठ १९३]

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बालभारती Mathematics and Statistics 2 (Arts and Science) [English] Standard 12 Maharashtra State Board
पाठ 6 Differential Equations
Exercise 6.1 | Q 6 | पृष्ठ १९३

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