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The order and degree of the differential equation [1+(dydx)3]23=8(d3ydx3) are respectively ______.

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प्रश्न

The order and degree of the differential equation `[1 + ((dy)/(dx))^3]^(2/3) = 8((d^3y)/(dx^3))` are respectively ______.

पर्याय

  • 3, 1

  • 1, 3

  • 3, 3

  • 1, 1

MCQ
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उत्तर

The order and degree of the differential equation `[1 + ((dy)/(dx))^3]^(2/3) = 8((d^3y)/(dx^3))` are respectively 3, 3.

Explanation:

Given: `[1 + ((dy)/(dx))^3]^(2/3) = 8((d^3y)/(dx^3))`

Taking cube on both sides

`[1 + ((dy)/(dx))^3]^2 = 8((d^3y)/(dx^3))^3`

∴ Order = 3

Degree = 3.

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