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प्रश्न
Order and degree of the differential equation `[1+(dy/dx)^3]^(7/3)=7(d^2y)/(dx^2)` are respectively
(A) 2, 3
(B) 3, 2
(C) 7, 2
(D) 3, 7
The order and degree of the differential equation `[1+(dy/dx)^3]^(7/3)=7(d^2y)/(dx^2)` are respectively
(A) 2, 3
(B) 3, 2
(C) 2, 2
(D) 3, 3
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उत्तर
`[1+(dy/dx)^3]^(7/3)=7(d^2y)/(dx^2)`
Cubing on both sides, we get
`[1+(dy/dx)^3]^(7)=7((d^2y)/(dx^2))^3`
By definition of degree and order Degree: 3 ; Order: 2
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