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The degree of the differential equation [1+(dydx)2]3=(d2ydx2)2 is ______. - Mathematics

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प्रश्न

The degree of the differential equation `[1 + (dy/dx)^2]^3 = ((d^2y)/(dx^2))^2` is ______.

विकल्प

  • 4

  • `3/2`

  • 2

  • Not defined

MCQ
रिक्त स्थान भरें
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उत्तर

The degree of the differential equation `[1 + (dy/dx)^2]^3 = ((d^2y)/(dx^2))^2` is 2.

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