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The degree of the differential equation dydxdydxxdydxd2ydx2+3(dydx)2=x2(d2ydx2)2 is: - Mathematics

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प्रश्न

The degree of the differential equation `("d"^2"y")/("dx"^2) + 3("dy"/"dx")^2 = "x"^2 (("d"^2"y")/("dx"^2))^2` is:

विकल्प

  • 1

  • 2

  • 3

  • 4

MCQ
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उत्तर

2

Explanation:

Given differential equation is

`("d"^2"y")/("dx"^2) + 3("dy"/"dx")^2 = "x"^2 (("d"^2"y")/("dx"^2))^2`

The degree of a differential equation is the degree of the highest order occurring in it.

So, the order of the differential equation is 2 and the degree of the differential equation is also 2.

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